Honeycomb lattice of graphene
The unit cell of graphene’s lattice consists of two different types of sites, which we will refer to as A and B sites (see Figure 1).
With the basis vectors, the cell can be defined by the cell vector
Rn=j⋅→a1+k⋅→a2Below we will used (j,k) to denote the cell index.
Nearest-neighbour Tighting Binding Model for Graphene
The Hamiltonian of the graphene lattice
ˆH=−ℏ22m∇2+U(r)where U(r) is the periodic potential of the crystal. The Schrödinger equation follows
[−ℏ22m∇2+U(r)]ψk(r)=E(k)ψk(r)where ψk(r) is the wavefunction of the electron, and E(r) is the corresponding energy.
Assuming that wα(r−Rn) are orthonormal wavefunctions located at site α of the cell Rn, i.e.
∫Vw∗α(r−Rn)wβ(r−Rm)dr=δαβδmnAccording to the Bloch’s theorem, the wavefunction of the electron in a periodic potential can be written as linear combination of the Bloch sum, i.e.
ψk(r)=1√N∑αCα(k)∑neik⋅Rnwα(r−Rn)By expanding the Hamiltonian in the Bloch sum basis, we have
H(k)=[H11H12H21H22]where Hαβ is given by
Hαβ=1N∑nm∫Veik⋅(Rm−Rn)w∗α(r−Rn)H(r)wβ(r−Rm)dr=∑n∫Veik⋅Rnw∗α(r−Rn)H(r)wβ(r−R0)drwhere we used the fact that the integrand only depends on the distance between the site Rn and Rm.
In the nearest-neighbours tight-binding model, we only considter those terms with |n|≤1.
The diagonal matrix elements
Apparently, only n=0 contributes to the matrix elements H11 and H22, therefore
H11=H22=∫Vw∗1(r−R0)H(r)w1(r−R0)dr=∫Vw∗2(r−R0)H(r)w2(r−R0)dr=ε0The off-diagonal matrix elements
Let’s first inspect the H12 term. One can see from Figure 1 that the nearest-neighbours of the A site in cell (j,k) located in the cell (j,k), (j−1,k) and (j,k−1), respectively. As a result, the H12 term can be readily written.
H12=∫Vw∗1(r−R0)H(r)w2(r−R0)dr+e−ik⋅a1∫Vw∗1(r−R(−1,0))H(r)w2(r−R0)dr+e−ik⋅a2∫Vw∗1(r−R(0,−1))H(r)w2(r−R0)drBy further assuming that the integral of the last three terms are the same, i.e.
t=∫Vw∗1(r−R0)H(r)w2(r−R0)drwe have
H12=t[1+e−ika1+e−ika2]Similarly, we have
H21=t[1+eika1+eika2]The complete matrix
Putting together all the matrix element, we have
H(k)=[ε0t[1+e−ika1+e−ika2]t[1+eika1+eika2]ε0]The eigenvalues E(k) can then be easily obtained
E(k)=ε0±t√1+e−ika1+eika1+e−ika2+eika2+(e−ika1+e−ika2)(eika1+eika2)=ε0±t√3+2cos(ka1)+2cos(ka2)+2cos(k(a1−a2))One of the definitions for the hexagonal lattice is
→a1=a2(3,√3)→a2=a2(3,−√3)where a is the bond-length of the graphene. With this definition, the energy band of graphene follows.
E(kx,ky)=±t√3+2cos(√3kya)+4cos(32kxa)cos(√32kya)